$$(\frac{x^{q}}{x^{b}})^{c}\times(\frac{x^{b}}{x^{c}})^{2}\times(\frac{x^{c}}{x^{a}})^{b}=1$$
$a=e^{\frac{Im(b)arg(\frac{x^{2\left(c-b\right)}}{\left(x^{q-b}\right)^{c}})+iRe(b)arg(\frac{x^{2\left(c-b\right)}}{\left(x^{q-b}\right)^{c}})}{\left(Re(b)\right)^{2}+\left(Im(b)\right)^{2}}-\frac{2\pi n_{1}iRe(b)}{\left(Re(b)\right)^{2}+\left(Im(b)\right)^{2}}-\frac{2\pi n_{1}Im(b)}{\left(Re(b)\right)^{2}+\left(Im(b)\right)^{2}}}\left(|x^{2\left(c-b\right)}||\frac{1}{\left(x^{q-b}\right)^{c}}|\right)^{\frac{Re(b)-iIm(b)}{\left(Re(b)\right)^{2}+\left(Im(b)\right)^{2}}}$
$n_{1}\in \mathrm{Z}$
$x\neq 0\text{ and }\left(c=0\text{ or }q=b\text{ or }\left(x^{q-b}\right)^{c}\neq 0\right)$