$$(\frac{y+2}{4})+3$$
$\frac{y+14}{4}$
$$\frac{y+2}{4}+\frac{3\times 4}{4}$$
$$\frac{y+2+3\times 4}{4}$$
$$\frac{y+2+12}{4}$$
$$\frac{y+14}{4}$$
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$\frac{y}{4}+\frac{7}{2}$