How to solve ) 17 8 ) 5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve ) 17 8 ) 5 | Equatix

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Question

$$( i ) | 7 \quad ( - 8 ) \quad 5$$

Evaluate

$280i$

Solution Steps

Multiply $7$ and $-8$ to get $-56$.

$$i|-56\times 5|$$

Multiply $-56$ and $5$ to get $-280$.

$$i|-280|$$

The modulus of a complex number $a+bi$ is $\sqrt{a^{2}+b^{2}}$. The modulus of $-280$ is $280$.

$$280i$$

Show Solution

Real Part

$0$

Solution Steps

Multiply $7$ and $-8$ to get $-56$.

$$Re(i|-56\times 5|)$$

Multiply $-56$ and $5$ to get $-280$.

$$Re(i|-280|)$$

The modulus of a complex number $a+bi$ is $\sqrt{a^{2}+b^{2}}$. The modulus of $-280$ is $280$.

$$Re(280i)$$

The real part of $280i$ is $0$.

$$0$$

Show Solution

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