Solve (ix) - 27 - [18 - \{16 - (9 - 8 - 1)\}]

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3(r+2s)=2t-4

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Question

$$(ix); -27-[18-\{16-(9-8-1)\}]$$

Evaluate

$x-29$

Solution Steps

Subtract $8$ from $9$ to get $1$.

$$x-27-\left(18-\left(16-\left(1-1\right)\right)\right)$$

Subtract $1$ from $1$ to get $0$.

$$x-27-\left(18-\left(16-0\right)\right)$$

Subtract $0$ from $16$ to get $16$.

$$x-27-\left(18-16\right)$$

Subtract $16$ from $18$ to get $2$.

$$x-27-2$$

Subtract $2$ from $-27$ to get $-29$.

$$x-29$$

Show Solution

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$x-29$

Solution Steps

Subtract $8$ from $9$ to get $1$.

$$x-27-\left(18-\left(16-\left(1-1\right)\right)\right)$$

Subtract $1$ from $1$ to get $0$.

$$x-27-\left(18-\left(16-0\right)\right)$$

Subtract $0$ from $16$ to get $16$.

$$x-27-\left(18-16\right)$$

Subtract $16$ from $18$ to get $2$.

$$x-27-2$$

Subtract $2$ from $-27$ to get $-29$.

$$x-29$$

Show Solution

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Solution Steps