Solve ( k) 3q + 9 = 18; 3p- | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( k ) 3 q + 9 = 18$$

Solve for k

$k=\frac{3}{q}$
$q\neq 0$

Steps for Solving Linear Equation

Subtract $9$ from both sides.

$$k\times 3q=18-9$$

Subtract $9$ from $18$ to get $9$.

$$k\times 3q=9$$

The equation is in standard form.

$$3qk=9$$

Divide both sides by $3q$.

$$\frac{3qk}{3q}=\frac{9}{3q}$$

Dividing by $3q$ undoes the multiplication by $3q$.

$$k=\frac{9}{3q}$$

Divide $9$ by $3q$.

$$k=\frac{3}{q}$$

Solve for q

$q=\frac{3}{k}$
$k\neq 0$

Steps for Solving Linear Equation

Subtract $9$ from both sides.

$$k\times 3q=18-9$$

Subtract $9$ from $18$ to get $9$.

$$k\times 3q=9$$

The equation is in standard form.

$$3kq=9$$

Divide both sides by $3k$.

$$\frac{3kq}{3k}=\frac{9}{3k}$$

Dividing by $3k$ undoes the multiplication by $3k$.

$$q=\frac{9}{3k}$$

Divide $9$ by $3k$.

$$q=\frac{3}{k}$$