Solve (k + 2) ^ 2 - 8(k + 2) + 16 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(k+2)^{2}-8(k+2)+16$$

Evaluate

$\left(k-2\right)^{2}$

Solution Steps

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(k+2\right)^{2}$.

$$k^{2}+4k+4-8\left(k+2\right)+16$$

Use the distributive property to multiply $-8$ by $k+2$.

$$k^{2}+4k+4-8k-16+16$$

Combine $4k$ and $-8k$ to get $-4k$.

$$k^{2}-4k+4-16+16$$

Subtract $16$ from $4$ to get $-12$.

$$k^{2}-4k-12+16$$

Add $-12$ and $16$ to get $4$.

$$k^{2}-4k+4$$

Expand

$k^{2}-4k+4$

Solution Steps

Use binomial theorem $\left(a+b\right)^{2}=a^{2}+2ab+b^{2}$ to expand $\left(k+2\right)^{2}$.

$$k^{2}+4k+4-8\left(k+2\right)+16$$

Use the distributive property to multiply $-8$ by $k+2$.

$$k^{2}+4k+4-8k-16+16$$

Combine $4k$ and $-8k$ to get $-4k$.

$$k^{2}-4k+4-16+16$$

Subtract $16$ from $4$ to get $-12$.

$$k^{2}-4k-12+16$$

Add $-12$ and $16$ to get $4$.

$$k^{2}-4k+4$$