Question

$$(m^{2})^{x}\times m^{(x+1)}=m^{-2}$$

Answer

x=-1

Solution


Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\[{m}^{2x}{m}^{x+1}={m}^{-2}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{m}^{2x+x+1}={m}^{-2}\]
Simplify  \(2x+x+1\)  to  \(3x+1\).
\[{m}^{3x+1}={m}^{-2}\]
Cancel the base of \(m\) on both sides.
\[3x+1=-2\]
Subtract \(1\) from both sides.
\[3x=-2-1\]
Simplify  \(-2-1\)  to  \(-3\).
\[3x=-3\]
Divide both sides by \(3\).
\[x=-1\]