How to solve (-1/9)-(-5/2)+7/6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-1/9)-(-5/2)+7/6 | Equatix

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Question

$$(-1/9)-(-5/2)+7/6$$

Evaluate

$\frac{32}{9}\approx 3.555555556$

Solution Steps

Fraction $\frac{-1}{9}$ can be rewritten as $-\frac{1}{9}$ by extracting the negative sign.

$$-\frac{1}{9}-\frac{-5}{2}+\frac{7}{6}$$

Fraction $\frac{-5}{2}$ can be rewritten as $-\frac{5}{2}$ by extracting the negative sign.

$$-\frac{1}{9}-\left(-\frac{5}{2}\right)+\frac{7}{6}$$

The opposite of $-\frac{5}{2}$ is $\frac{5}{2}$.

$$-\frac{1}{9}+\frac{5}{2}+\frac{7}{6}$$

Least common multiple of $9$ and $2$ is $18$. Convert $-\frac{1}{9}$ and $\frac{5}{2}$ to fractions with denominator $18$.

$$-\frac{2}{18}+\frac{45}{18}+\frac{7}{6}$$

Since $-\frac{2}{18}$ and $\frac{45}{18}$ have the same denominator, add them by adding their numerators.

$$\frac{-2+45}{18}+\frac{7}{6}$$

Add $-2$ and $45$ to get $43$.

$$\frac{43}{18}+\frac{7}{6}$$

Least common multiple of $18$ and $6$ is $18$. Convert $\frac{43}{18}$ and $\frac{7}{6}$ to fractions with denominator $18$.

$$\frac{43}{18}+\frac{21}{18}$$

Since $\frac{43}{18}$ and $\frac{21}{18}$ have the same denominator, add them by adding their numerators.

$$\frac{43+21}{18}$$

Add $43$ and $21$ to get $64$.

$$\frac{64}{18}$$

Reduce the fraction $\frac{64}{18}$ to lowest terms by extracting and canceling out $2$.

$$\frac{32}{9}$$

Show Solution

Factor

$\frac{2 ^ {5}}{3 ^ {2}} = 3\frac{5}{9} = 3.5555555555555554$