$$(-1\frac{3}{25})-2\frac{7}{7}+(-2\frac{1}{9})\cdot(-\frac{27}{790})$$
$-\frac{15989}{3950}\approx -4.047848101$
$$-\frac{25+3}{25}-\frac{2\times 7+7}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{28}{25}-\frac{2\times 7+7}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{28}{25}-\frac{14+7}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{28}{25}-\frac{21}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{28}{25}-3+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{28}{25}-\frac{75}{25}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$\frac{-28-75}{25}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{103}{25}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{103}{25}+\left(-\frac{18+1}{9}\right)\left(-\frac{27}{790}\right)$$
$$-\frac{103}{25}-\frac{19}{9}\left(-\frac{27}{790}\right)$$
$$-\frac{103}{25}+\frac{-19\left(-27\right)}{9\times 790}$$
$$-\frac{103}{25}+\frac{513}{7110}$$
$$-\frac{103}{25}+\frac{57}{790}$$
$$-\frac{16274}{3950}+\frac{285}{3950}$$
$$\frac{-16274+285}{3950}$$
$$-\frac{15989}{3950}$$
Show Solution
Hide Solution
$-\frac{15989}{3950} = -4\frac{189}{3950} = -4.0478481012658225$
