Solve (-12+-9/11)+7/-12=-12+(-9/11+7/-12) | Equatix - Math Solver

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3(r+2s)=2t-4

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Question

$$(-12+-9/11)+7/-12=-12+(-9/11+7/-12)$$

Verify

$\text{true}$

Solution Steps

Fraction $\frac{-9}{11}$ can be rewritten as $-\frac{9}{11}$ by extracting the negative sign.

$$-12-\frac{9}{11}+\frac{7}{-12}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Convert $-12$ to fraction $-\frac{132}{11}$.

$$-\frac{132}{11}-\frac{9}{11}+\frac{7}{-12}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Since $-\frac{132}{11}$ and $\frac{9}{11}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-132-9}{11}+\frac{7}{-12}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Subtract $9$ from $-132$ to get $-141$.

$$-\frac{141}{11}+\frac{7}{-12}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Fraction $\frac{7}{-12}$ can be rewritten as $-\frac{7}{12}$ by extracting the negative sign.

$$-\frac{141}{11}-\frac{7}{12}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Least common multiple of $11$ and $12$ is $132$. Convert $-\frac{141}{11}$ and $\frac{7}{12}$ to fractions with denominator $132$.

$$-\frac{1692}{132}-\frac{77}{132}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Since $-\frac{1692}{132}$ and $\frac{77}{132}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1692-77}{132}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Subtract $77$ from $-1692$ to get $-1769$.

$$-\frac{1769}{132}=-12+\frac{-9}{11}+\frac{7}{-12}$$

Fraction $\frac{-9}{11}$ can be rewritten as $-\frac{9}{11}$ by extracting the negative sign.

$$-\frac{1769}{132}=-12-\frac{9}{11}+\frac{7}{-12}$$

Convert $-12$ to fraction $-\frac{132}{11}$.

$$-\frac{1769}{132}=-\frac{132}{11}-\frac{9}{11}+\frac{7}{-12}$$

Since $-\frac{132}{11}$ and $\frac{9}{11}$ have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1769}{132}=\frac{-132-9}{11}+\frac{7}{-12}$$

Subtract $9$ from $-132$ to get $-141$.

$$-\frac{1769}{132}=-\frac{141}{11}+\frac{7}{-12}$$

Fraction $\frac{7}{-12}$ can be rewritten as $-\frac{7}{12}$ by extracting the negative sign.

$$-\frac{1769}{132}=-\frac{141}{11}-\frac{7}{12}$$

Least common multiple of $11$ and $12$ is $132$. Convert $-\frac{141}{11}$ and $\frac{7}{12}$ to fractions with denominator $132$.

$$-\frac{1769}{132}=-\frac{1692}{132}-\frac{77}{132}$$

Since $-\frac{1692}{132}$ and $\frac{77}{132}$ have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1769}{132}=\frac{-1692-77}{132}$$

Subtract $77$ from $-1692$ to get $-1769$.

$$-\frac{1769}{132}=-\frac{1769}{132}$$

Compare $-\frac{1769}{132}$ and $-\frac{1769}{132}$.

$$\text{true}$$