$$(-13+54/3) \times (-8)-161/(-7)$$
$-17$
$$\left(-13+18\right)\left(-8\right)-\frac{161}{-7}$$
$$5\left(-8\right)-\frac{161}{-7}$$
$$-40-\frac{161}{-7}$$
$$-40-\left(-23\right)$$
$$-40+23$$
$$-17$$
Show Solution
Hide Solution