$$(-16n-8) \times ( \frac{ 3 }{ 4 } )$$
$-12n-6$
$$-16n\times \frac{3}{4}-8\times \frac{3}{4}$$
$$\frac{-16\times 3}{4}n-8\times \frac{3}{4}$$
$$\frac{-48}{4}n-8\times \frac{3}{4}$$
$$-12n-8\times \frac{3}{4}$$
$$-12n+\frac{-8\times 3}{4}$$
$$-12n+\frac{-24}{4}$$
$$-12n-6$$
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