How to solve (-18-2)-[+4+(-6)]

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-18-2)-[+4+(-6)] | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-18-2)-[+4+(-6)]$$

Evaluate

$-18$

Solution Steps

Subtract $2$ from $-18$ to get $-20$.

$$-20-\left(4-6\right)$$

Subtract $6$ from $4$ to get $-2$.

$$-20-\left(-2\right)$$

The opposite of $-2$ is $2$.

$$-20+2$$

Add $-20$ and $2$ to get $-18$.

$$-18$$

Show Solution

Factor

$-18$

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