Solve (-18-2)-[+4+(-6)]\div2+5 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-18-2)-[+4+(-6)] \div 2+5$$

Evaluate

$-14$

Solution Steps

Subtract $2$ from $-18$ to get $-20$.

$$-20-\frac{4-6}{2}+5$$

Subtract $6$ from $4$ to get $-2$.

$$-20-\frac{-2}{2}+5$$

Divide $-2$ by $2$ to get $-1$.

$$-20-\left(-1\right)+5$$

The opposite of $-1$ is $1$.

$$-20+1+5$$

Add $-20$ and $1$ to get $-19$.

$$-19+5$$

Add $-19$ and $5$ to get $-14$.

$$-14$$

Factor

$-14$