How to solve (-2/3+3/5)+(-5/9)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-2/3+3/5)+(-5/9) | Equatix

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Question

$$(-2/3+3/5)+(-5/9)$$

Evaluate

$-\frac{28}{45}\approx -0.622222222$

Solution Steps

Fraction $\frac{-2}{3}$ can be rewritten as $-\frac{2}{3}$ by extracting the negative sign.

$$-\frac{2}{3}+\frac{3}{5}+\frac{-5}{9}$$

Least common multiple of $3$ and $5$ is $15$. Convert $-\frac{2}{3}$ and $\frac{3}{5}$ to fractions with denominator $15$.

$$-\frac{10}{15}+\frac{9}{15}+\frac{-5}{9}$$

Since $-\frac{10}{15}$ and $\frac{9}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{-10+9}{15}+\frac{-5}{9}$$

Add $-10$ and $9$ to get $-1$.

$$-\frac{1}{15}+\frac{-5}{9}$$

Fraction $\frac{-5}{9}$ can be rewritten as $-\frac{5}{9}$ by extracting the negative sign.

$$-\frac{1}{15}-\frac{5}{9}$$

Least common multiple of $15$ and $9$ is $45$. Convert $-\frac{1}{15}$ and $\frac{5}{9}$ to fractions with denominator $45$.

$$-\frac{3}{45}-\frac{25}{45}$$

Since $-\frac{3}{45}$ and $\frac{25}{45}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-25}{45}$$

Subtract $25$ from $-3$ to get $-28$.

$$-\frac{28}{45}$$

Show Solution

Factor

$-\frac{28}{45} = -0.6222222222222222$