How to solve (-2/5-3/10)-5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-2/5-3/10)-5 | Equatix

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Question

$$(-2/5-3/10)-5$$

Evaluate

$-\frac{57}{10}=-5.7$

Solution Steps

Fraction $\frac{-2}{5}$ can be rewritten as $-\frac{2}{5}$ by extracting the negative sign.

$$-\frac{2}{5}-\frac{3}{10}-5$$

Least common multiple of $5$ and $10$ is $10$. Convert $-\frac{2}{5}$ and $\frac{3}{10}$ to fractions with denominator $10$.

$$-\frac{4}{10}-\frac{3}{10}-5$$

Since $-\frac{4}{10}$ and $\frac{3}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-3}{10}-5$$

Subtract $3$ from $-4$ to get $-7$.

$$-\frac{7}{10}-5$$

Convert $5$ to fraction $\frac{50}{10}$.

$$-\frac{7}{10}-\frac{50}{10}$$

Since $-\frac{7}{10}$ and $\frac{50}{10}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-50}{10}$$

Subtract $50$ from $-7$ to get $-57$.

$$-\frac{57}{10}$$

Show Solution

Factor

$-\frac{57}{10} = -5\frac{7}{10} = -5.7$