How to solve |(-2-3)(4)+5=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve |(-2-3)(4)+5= | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$|(-2-3)(4)+5=$$

Evaluate

$15$

Solution Steps

Subtract $3$ from $-2$ to get $-5$.

$$|-5\times 4+5|$$

Multiply $-5$ and $4$ to get $-20$.

$$|-20+5|$$

Add $-20$ and $5$ to get $-15$.

$$|-15|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-15$ is $15$.

$$15$$

Show Solution

Factor

$3\times 5$

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