$$(-2+4 { n }^{ 2 } + { n }^{ 4 } )+(-6 { n }^{ 3 } -8-2 { n }^{ 2 } )$$
$n^{4}-6n^{3}+2n^{2}-10$
$$-10+4n^{2}+n^{4}-6n^{3}-2n^{2}$$
$$-10+2n^{2}+n^{4}-6n^{3}$$
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$2n\left(2n^{2}-9n+2\right)$
$$\frac{\mathrm{d}}{\mathrm{d}n}(-10+4n^{2}+n^{4}-6n^{3}-2n^{2})$$
$$\frac{\mathrm{d}}{\mathrm{d}n}(-10+2n^{2}+n^{4}-6n^{3})$$
$$2\times 2n^{2-1}+4n^{4-1}+3\left(-6\right)n^{3-1}$$
$$4n^{2-1}+4n^{4-1}+3\left(-6\right)n^{3-1}$$
$$4n^{1}+4n^{4-1}+3\left(-6\right)n^{3-1}$$
$$4n^{1}+4n^{3}+3\left(-6\right)n^{3-1}$$
$$4n^{1}+4n^{3}-18n^{3-1}$$
$$4n^{1}+4n^{3}-18n^{2}$$
$$4n+4n^{3}-18n^{2}$$
