Solve (-2+-2/3)+-3/4=-2+(-2/3+-3/4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-2+-2/3)+-3/4=-2+(-2/3+-3/4)$$

Verify

$\text{true}$

Solution Steps

Fraction $\frac{-2}{3}$ can be rewritten as $-\frac{2}{3}$ by extracting the negative sign.

$$-2-\frac{2}{3}+\frac{-3}{4}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Convert $-2$ to fraction $-\frac{6}{3}$.

$$-\frac{6}{3}-\frac{2}{3}+\frac{-3}{4}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Since $-\frac{6}{3}$ and $\frac{2}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-6-2}{3}+\frac{-3}{4}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Subtract $2$ from $-6$ to get $-8$.

$$-\frac{8}{3}+\frac{-3}{4}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$-\frac{8}{3}-\frac{3}{4}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Least common multiple of $3$ and $4$ is $12$. Convert $-\frac{8}{3}$ and $\frac{3}{4}$ to fractions with denominator $12$.

$$-\frac{32}{12}-\frac{9}{12}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Since $-\frac{32}{12}$ and $\frac{9}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-32-9}{12}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Subtract $9$ from $-32$ to get $-41$.

$$-\frac{41}{12}=-2+\frac{-2}{3}+\frac{-3}{4}$$

Fraction $\frac{-2}{3}$ can be rewritten as $-\frac{2}{3}$ by extracting the negative sign.

$$-\frac{41}{12}=-2-\frac{2}{3}+\frac{-3}{4}$$

Convert $-2$ to fraction $-\frac{6}{3}$.

$$-\frac{41}{12}=-\frac{6}{3}-\frac{2}{3}+\frac{-3}{4}$$

Since $-\frac{6}{3}$ and $\frac{2}{3}$ have the same denominator, subtract them by subtracting their numerators.

$$-\frac{41}{12}=\frac{-6-2}{3}+\frac{-3}{4}$$

Subtract $2$ from $-6$ to get $-8$.

$$-\frac{41}{12}=-\frac{8}{3}+\frac{-3}{4}$$

Fraction $\frac{-3}{4}$ can be rewritten as $-\frac{3}{4}$ by extracting the negative sign.

$$-\frac{41}{12}=-\frac{8}{3}-\frac{3}{4}$$

Least common multiple of $3$ and $4$ is $12$. Convert $-\frac{8}{3}$ and $\frac{3}{4}$ to fractions with denominator $12$.

$$-\frac{41}{12}=-\frac{32}{12}-\frac{9}{12}$$

Since $-\frac{32}{12}$ and $\frac{9}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$-\frac{41}{12}=\frac{-32-9}{12}$$

Subtract $9$ from $-32$ to get $-41$.

$$-\frac{41}{12}=-\frac{41}{12}$$

Compare $-\frac{41}{12}$ and $-\frac{41}{12}$.

$$\text{true}$$