Solve (-21)\times[(-4)+(-6)]=[(-21)\times(-4)]+[(-21)\times(-6)] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-21) \times [(-4)+(-6)]=[(-21) \times (-4)]+[(-21) \times (-6)]$$

Verify

$\text{true}$

Solution Steps

Subtract $6$ from $-4$ to get $-10$.

$$-21\left(-10\right)=-21\left(-4\right)-21\left(-6\right)$$

Multiply $-21$ and $-10$ to get $210$.

$$210=-21\left(-4\right)-21\left(-6\right)$$

Multiply $-21$ and $-4$ to get $84$. Multiply $-21$ and $-6$ to get $126$.

$$210=84+126$$

Add $84$ and $126$ to get $210$.

$$210=210$$

Compare $210$ and $210$.

$$\text{true}$$