$$(-2x+\frac{1}{3}y)^{2}$$
$\frac{\left(y-6x\right)^{2}}{9}$
$$4x^{2}-\frac{4}{3}xy+\frac{1}{9}y^{2}$$
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$-\frac{4xy}{3}+\frac{y^{2}}{9}+4x^{2}$
