$$(-2x^{3})(4x^{2})=$$
$-8x^{5}$
$$-2x^{5}\times 4$$
$$-8x^{5}$$
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$-40x^{4}$
$$\frac{\mathrm{d}}{\mathrm{d}x}(-2x^{5}\times 4)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(-8x^{5})$$
$$5\left(-8\right)x^{5-1}$$
$$-40x^{5-1}$$
$$-40x^{4}$$
