Solve (-2x3+3x4-6+x)\divx+2= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-2x3+3x4-6+x) \div x+2=$$

Evaluate

$\frac{3x-2x_{3}+3x_{4}-6}{x}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $2$ times $\frac{x}{x}$.

$$\frac{-2x_{3}+3x_{4}-6+x}{x}+\frac{2x}{x}$$

Since $\frac{-2x_{3}+3x_{4}-6+x}{x}$ and $\frac{2x}{x}$ have the same denominator, add them by adding their numerators.

$$\frac{-2x_{3}+3x_{4}-6+x+2x}{x}$$

Combine like terms in $-2x_{3}+3x_{4}-6+x+2x$.

$$\frac{-2x_{3}+3x_{4}-6+3x}{x}$$

Expand

$\frac{3x-2x_{3}+3x_{4}-6}{x}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $2$ times $\frac{x}{x}$.

$$\frac{-2x_{3}+3x_{4}-6+x}{x}+\frac{2x}{x}$$

Since $\frac{-2x_{3}+3x_{4}-6+x}{x}$ and $\frac{2x}{x}$ have the same denominator, add them by adding their numerators.

$$\frac{-2x_{3}+3x_{4}-6+x+2x}{x}$$

Combine like terms in $-2x_{3}+3x_{4}-6+x+2x$.

$$\frac{-2x_{3}+3x_{4}-6+3x}{x}$$