$$(-3) \times (-2) \div (+6) \times (-18) \div (-1)$$
$18$
$$\frac{\frac{6}{6}\left(-18\right)}{-1}$$
$$\frac{1\left(-18\right)}{-1}$$
$$\frac{-18}{-1}$$
$$18$$
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$2\times 3^{2}$