$$(-3) \times (-4)-(-24)/6-5 \times 3$$
$1$
$$12-\frac{-24}{6}-5\times 3$$
$$12-\left(-4\right)-5\times 3$$
$$12+4-5\times 3$$
$$16-5\times 3$$
$$16-15$$
$$1$$
Show Solution
Hide Solution
