Solve (-42)\times[(-3)+(-7)]=[(-42)\times(-3)]+[(-42)\times(-7)] | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-42) \times [(-3)+(-7)]=[(-42) \times (-3)]+[(-42) \times (-7)]$$

Verify

$\text{true}$

Solution Steps

Subtract $7$ from $-3$ to get $-10$.

$$-42\left(-10\right)=-42\left(-3\right)-42\left(-7\right)$$

Multiply $-42$ and $-10$ to get $420$.

$$420=-42\left(-3\right)-42\left(-7\right)$$

Multiply $-42$ and $-3$ to get $126$. Multiply $-42$ and $-7$ to get $294$.

$$420=126+294$$

Add $126$ and $294$ to get $420$.

$$420=420$$

Compare $420$ and $420$.

$$\text{true}$$