Solve (-5)(-3+4-6)+(11-15+7)(-9)+23 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-5)(-3+4-6)+(11-15+7)(-9)+23$$

Evaluate

$21$

Solution Steps

Add $-3$ and $4$ to get $1$.

$$-5\left(1-6\right)+\left(11-15+7\right)\left(-9\right)+23$$

Subtract $6$ from $1$ to get $-5$.

$$-5\left(-5\right)+\left(11-15+7\right)\left(-9\right)+23$$

Multiply $-5$ and $-5$ to get $25$.

$$25+\left(11-15+7\right)\left(-9\right)+23$$

Subtract $15$ from $11$ to get $-4$.

$$25+\left(-4+7\right)\left(-9\right)+23$$

Add $-4$ and $7$ to get $3$.

$$25+3\left(-9\right)+23$$

Multiply $3$ and $-9$ to get $-27$.

$$25-27+23$$

Subtract $27$ from $25$ to get $-2$.

$$-2+23$$

Add $-2$ and $23$ to get $21$.

$$21$$

Factor

$3\times 7$