$$(-5x^{3}y+20x^{2}y^{2})\div(-5xy)$$
$x\left(x-4y\right)$
$$\frac{5y\left(-x+4y\right)x^{2}}{-5xy}$$
$$\frac{x\left(-x+4y\right)}{-1}$$
$$x^{2}-4xy$$
Show Solution
Hide Solution
$x^{2}-4xy$