$$(-6\cdot\frac{-4}{3}\times\frac{-13}{9})-(\frac{2}{5}-\frac{4}{3})$$
$-\frac{478}{45}\approx -10.622222222$
$$-6\left(-\frac{4}{3}\right)\times \frac{-13}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$\frac{-6\left(-4\right)}{3}\times \frac{-13}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$\frac{24}{3}\times \frac{-13}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$8\times \frac{-13}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$8\left(-\frac{13}{9}\right)-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$\frac{8\left(-13\right)}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$\frac{-104}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$-\frac{104}{9}-\left(\frac{2}{5}-\frac{4}{3}\right)$$
$$-\frac{104}{9}-\left(\frac{6}{15}-\frac{20}{15}\right)$$
$$-\frac{104}{9}-\frac{6-20}{15}$$
$$-\frac{104}{9}-\left(-\frac{14}{15}\right)$$
$$-\frac{104}{9}+\frac{14}{15}$$
$$-\frac{520}{45}+\frac{42}{45}$$
$$\frac{-520+42}{45}$$
$$-\frac{478}{45}$$
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$-\frac{478}{45} = -10\frac{28}{45} = -10.622222222222222$
