$$(-6)\dot{\times}(-8); +\frac{1}{3}\times\frac{-3}{2}$$
$\frac{1}{2},48$
$$sort(48,\frac{1}{3}\times \frac{3}{2})$$
$$sort(48,\frac{1\times 3}{3\times 2})$$
$$sort(48,\frac{1}{2})$$
$$48,\frac{1}{2}$$
$$48$$
$$\frac{1}{2},48$$
Show Solution
Hide Solution
$48,\ \frac{1}{2}$
