Solve (-6)+[(-8)+12]=[(-6)+(-8)]+12 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-6)+[(-8)+12]=[(-6)+(-8)]+12$$

Verify

$\text{true}$

Solution Steps

Subtract $8$ from $-6$ to get $-14$.

$$-14+12=-6-8+12$$

Add $-14$ and $12$ to get $-2$.

$$-2=-6-8+12$$

Subtract $8$ from $-6$ to get $-14$.

$$-2=-14+12$$

Add $-14$ and $12$ to get $-2$.

$$-2=-2$$

Compare $-2$ and $-2$.

$$\text{true}$$