$$(-7)^{3}\times(\frac{1}{-7})^{5}$$
$\frac{1}{49}\approx 0.020408163$
$$-343\times \left(\frac{1}{-7}\right)^{5}$$
$$-343\left(-\frac{1}{7}\right)^{5}$$
$$-343\left(-\frac{1}{16807}\right)$$
$$\frac{1}{49}$$
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$\frac{1}{7 ^ {2}} = 0.02040816326530612$
