How to solve (- 8) / (4/delta)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (- 8) / (4/delta) | Equatix

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$$(-8)\div\frac{4}{\delta}$$

$-2\delta $

$-2$

Divide $-8$ by $\frac{4}{\delta }$ by multiplying $-8$ by the reciprocal of $\frac{4}{\delta }$.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\frac{-8\delta }{4})$$

Divide $-8\delta $ by $4$ to get $-2\delta $.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(-2\delta )$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$-2\delta ^{1-1}$$

Subtract $1$ from $1$.

$$-2\delta ^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$-2$$