$$[(-8)^{-4}\div2^{-8}]^{2}$$
$\frac{1}{256}=0.00390625$
$$\left(\frac{\frac{1}{4096}}{2^{-8}}\right)^{2}$$
$$\left(\frac{\frac{1}{4096}}{\frac{1}{256}}\right)^{2}$$
$$\left(\frac{1}{4096}\times 256\right)^{2}$$
$$\left(\frac{1}{16}\right)^{2}$$
$$\frac{1}{256}$$
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$\frac{1}{2 ^ {8}} = 0.00390625$
