Solve (-8+3)\times[(-7)\times(2)-(2)]+6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(-8+3) \times [(-7) \times (2)-(2)]+6$$

Evaluate

$86$

Solution Steps

Add $-8$ and $3$ to get $-5$.

$$-5\left(-7\times 2-2\right)+6$$

Multiply $-7$ and $2$ to get $-14$.

$$-5\left(-14-2\right)+6$$

Subtract $2$ from $-14$ to get $-16$.

$$-5\left(-16\right)+6$$

Multiply $-5$ and $-16$ to get $80$.

$$80+6$$

Add $80$ and $6$ to get $86$.

$$86$$

Factor

$2\times 43$