$$(-8+3) \times [(-7) \times (2)-(2) \times (2)]+6=$$
$96$
$$-5\left(-7\times 2-2\times 2\right)+6$$
$$-5\left(-14-2\times 2\right)+6$$
$$-5\left(-14-4\right)+6$$
$$-5\left(-18\right)+6$$
$$90+6$$
$$96$$
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$2^{5}\times 3$
