Solve (-(1)^(3))+(-(1)^(2))+(-1)+5= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(- { 1 }^{ 3 } )+(- { 1 }^{ 2 } )+(-1)+5=$$

Evaluate

$2$

Solution Steps

Calculate $1$ to the power of $3$ and get $1$.

$$-1-1^{2}-1+5$$

Calculate $1$ to the power of $2$ and get $1$.

$$-1-1-1+5$$

Subtract $1$ from $-1$ to get $-2$.

$$-2-1+5$$

Subtract $1$ from $-2$ to get $-3$.

$$-3+5$$

Add $-3$ and $5$ to get $2$.

$$2$$

Factor

$2$