How to solve (-r)+8+(-4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (-r)+8+(-4) | Equatix

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Question

$$(-r)+8+(-4)$$

Differentiate w.r.t. r

$-1$

Steps Using Derivative Rule for Sum

Subtract $4$ from $8$ to get $4$.

$$\frac{\mathrm{d}}{\mathrm{d}r}(-r+4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$-r^{1-1}$$

Subtract $1$ from $1$.

$$-r^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$-1$$

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Evaluate

$4-r$

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Example

Question

Differentiate w.r.t. r

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps