Question

$$( ) : \frac { 2 x + 6 } { x ^ { 2 } - 9 } - \frac { 4 x } { 2 x ^ { 2 } - 6 x } \quad [ 2 U ] ( 0 )$$

Answer

-(2*(2*s*U]An-Si*IM*m*p*l*f*y))/(x-3):0

Solution


Factor out the common term \(2\).
Rewrite \({x}^{2}-9\) in the form \({a}^{2}-{b}^{2}\), where \(a=x\) and \(b=3\).
Use Difference of Squares: \({a}^{2}-{b}^{2}=(a+b)(a-b)\).
Factor out the common term \(2x\).
Cancel \(x+3\).
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
Regroup terms.
Cancel \(x\).
Simplify  \(\frac{4}{2(x-3)}\)  to  \(\frac{2}{x-3}\).
Regroup terms.
Join the denominators.
Factor out the common term \(2\).
Move the negative sign to the left.