$$((14-5)+(20\div10)^{2})\times3^{2}$$
$117$
$$\left(9+\left(\frac{20}{10}\right)^{2}\right)\times 3^{2}$$
$$\left(9+2^{2}\right)\times 3^{2}$$
$$\left(9+4\right)\times 3^{2}$$
$$13\times 3^{2}$$
$$13\times 9$$
$$117$$
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$3^{2}\times 13$
