Question

$$((2^{x}+\frac{1}{x}+ln\ x-\log_{11}^{x})^{3})^{1}=$$

Answer

$$(2^x+x+ln(x)-log(11,^x))^3$$

Solution


Simplify  \(1\times x\)  to  \(x\).
\[{({({2}^{x}+x+\ln{x}-\log_{11}{{}^{x}})}^{3})}^{1}\]
Use Rule of One: \({x}^{1}=x\).
\[{({2}^{x}+x+\ln{x}-\log_{11}{{}^{x}})}^{3}\]