$$((221 { p }^{ 2 } { q }^{ 2 } +13p { q }^{ 2 } +17p { q }^{ 2 } ) \frac{ 6 }{ 1 }$$
$6p\left(221p+30\right)q^{2}$
$180pq^{2}+1326\left(pq\right)^{2}$
