$$((\frac{-3}{2})^{-2})^{-1}$$
$\frac{9}{4}=2.25$
$$\frac{1}{\left(-\frac{3}{2}\right)^{-2}}$$
$$\left(-\frac{3}{2}\right)^{-2\left(-1\right)}$$
$$\left(-\frac{3}{2}\right)^{2}$$
$$\frac{9}{4}$$
Show Solution
Hide Solution
$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$
