$$(+\frac{11}{4})-(\frac{7}{2})+(\frac{9}{5})+(2)$$
$\frac{61}{20}=3.05$
$$\frac{11}{4}-\frac{14}{4}+\frac{9}{5}+2$$
$$\frac{11-14}{4}+\frac{9}{5}+2$$
$$-\frac{3}{4}+\frac{9}{5}+2$$
$$-\frac{15}{20}+\frac{36}{20}+2$$
$$\frac{-15+36}{20}+2$$
$$\frac{21}{20}+2$$
$$\frac{21}{20}+\frac{40}{20}$$
$$\frac{21+40}{20}$$
$$\frac{61}{20}$$
Show Solution
Hide Solution
$\frac{61}{2 ^ {2} \cdot 5} = 3\frac{1}{20} = 3.05$