How to solve (sqrt(3) - 1) ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (sqrt(3) - 1) ^ 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(\sqrt{3}-1)^{2}$$

Evaluate

$4-2\sqrt{3}\approx 0.535898385$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(\sqrt{3}-1\right)^{2}$.

$$\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1$$

The square of $\sqrt{3}$ is $3$.

$$3-2\sqrt{3}+1$$

Add $3$ and $1$ to get $4$.

$$4-2\sqrt{3}$$

Show Solution

Expand

$4-2\sqrt{3}$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(\sqrt{3}-1\right)^{2}$.

$$\left(\sqrt{3}\right)^{2}-2\sqrt{3}+1$$

The square of $\sqrt{3}$ is $3$.

$$3-2\sqrt{3}+1$$

Add $3$ and $1$ to get $4$.

$$4-2\sqrt{3}$$

Show Solution

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Question

Evaluate

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Solution Steps