Question

$$( \sqrt { 3 } - \sqrt { 2 } ) ( \sqrt { 3 } + \sqrt { 2 } ) = \cdots \cdots \cdots \cdots \cdots$$

Answer

5

Solution


Use Difference of Squares: \({a}^{2}-{b}^{2}=(a+b)(a-b)\).
\[5({\sqrt{3}}^{2}-{\sqrt{2}}^{2})\]
Use this rule: \({\sqrt{x}}^{2}=x\).
\[5(3-{\sqrt{2}}^{2})\]
Use this rule: \({\sqrt{x}}^{2}=x\).
\[5\times (3-2)\]
Simplify  \(3-2\)  to  \(1\).
\[5\times 1\]
Simplify.
\[5\]