$$(\sqrt{3}+\sqrt{2})^{2}$$
$2\sqrt{6}+5\approx 9.898979486$
$$\left(\sqrt{3}\right)^{2}+2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$
$$3+2\sqrt{3}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$
$$3+2\sqrt{6}+\left(\sqrt{2}\right)^{2}$$
$$3+2\sqrt{6}+2$$
$$5+2\sqrt{6}$$
Show Solution
Hide Solution
$2 \sqrt{6} + 5 = 9.898979486$
