Question

$$(u^{2}+2x+3); -(2x^{2}+3); +(4^{3}+2+1)$$

Answer

$$u^2+2*x+3;-2*x^2-3;64+2+1$$

Solution


Simplify  \({4}^{3}\)  to  \(64\).
\[\begin{aligned}&{u}^{2}+2x+3\\&-(2{x}^{2}+3)\\&64+2+1\end{aligned}\]
Remove parentheses.
\[\begin{aligned}&{u}^{2}+2x+3\\&-2{x}^{2}-3\\&64+2+1\end{aligned}\]