Solve (u ^ 4 - 3u ^ 3 + 2u + 6) + (u ^ 4 - 3u ^ 2 + 6u + 2) - (u ^ 3 - 3u + 4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(u^{4}-3u^{3}+2u+6)+(u^{4}-3u^{2}+6u+2)-(u^{3}-3u+4)$$

Evaluate

$2u^{4}-4u^{3}-3u^{2}+11u+4$

Solution Steps

Combine $u^{4}$ and $u^{4}$ to get $2u^{4}$.

$$2u^{4}-3u^{3}+2u+6-3u^{2}+6u+2-\left(u^{3}-3u+4\right)$$

Combine $2u$ and $6u$ to get $8u$.

$$2u^{4}-3u^{3}+8u+6-3u^{2}+2-\left(u^{3}-3u+4\right)$$

Add $6$ and $2$ to get $8$.

$$2u^{4}-3u^{3}+8u+8-3u^{2}-\left(u^{3}-3u+4\right)$$

To find the opposite of $u^{3}-3u+4$, find the opposite of each term.

$$2u^{4}-3u^{3}+8u+8-3u^{2}-u^{3}+3u-4$$

Combine $-3u^{3}$ and $-u^{3}$ to get $-4u^{3}$.

$$2u^{4}-4u^{3}+8u+8-3u^{2}+3u-4$$

Combine $8u$ and $3u$ to get $11u$.

$$2u^{4}-4u^{3}+11u+8-3u^{2}-4$$

Subtract $4$ from $8$ to get $4$.

$$2u^{4}-4u^{3}+11u+4-3u^{2}$$

Expand

$2u^{4}-4u^{3}-3u^{2}+11u+4$

Solution Steps

Combine $u^{4}$ and $u^{4}$ to get $2u^{4}$.

$$2u^{4}-3u^{3}+2u+6-3u^{2}+6u+2-\left(u^{3}-3u+4\right)$$

Combine $2u$ and $6u$ to get $8u$.

$$2u^{4}-3u^{3}+8u+6-3u^{2}+2-\left(u^{3}-3u+4\right)$$

Add $6$ and $2$ to get $8$.

$$2u^{4}-3u^{3}+8u+8-3u^{2}-\left(u^{3}-3u+4\right)$$

To find the opposite of $u^{3}-3u+4$, find the opposite of each term.

$$2u^{4}-3u^{3}+8u+8-3u^{2}-u^{3}+3u-4$$

Combine $-3u^{3}$ and $-u^{3}$ to get $-4u^{3}$.

$$2u^{4}-4u^{3}+8u+8-3u^{2}+3u-4$$

Combine $8u$ and $3u$ to get $11u$.

$$2u^{4}-4u^{3}+11u+8-3u^{2}-4$$

Subtract $4$ from $8$ to get $4$.

$$2u^{4}-4u^{3}+11u+4-3u^{2}$$