Question

$$(v)\frac{2^{p+1}3^{2p-q}5^{p+q}6^{q}}{6^{p}}\frac{10^{q+2}15^{p}}$$

Answer

$$v*2^p+169*p-q*5^p+q*6^(q+p)*10^q+215^p$$

Solution


Simplify  \({13}^{2}\)  to  \(169\).
\[v\times {2}^{p}+169p-q\times {5}^{p}+q\times {6}^{q}\times {6}^{p}\times {10}^{q}+{215}^{p}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[v\times {2}^{p}+169p-q\times {5}^{p}+q\times {6}^{q+p}\times {10}^{q}+{215}^{p}\]